twice a number decreased by 58
/F3 17 0 R /ProcSet[/PDF] >> Q q /Meta308 322 0 R 0 G 0 5.203 TD (1\)) Tj 150 0 obj >> 1 i /Type /XObject /Resources<< >> << /Matrix [1 0 0 1 0 0] 1 i /Subtype /Form /FormType 1 /BBox [0 0 15.59 16.44] Q endstream q 1 g Q Q 1 i Q q q q (6\)) Tj /Meta55 69 0 R 0 g 0 g 0.564 G /Meta255 Do endobj Q 1 i endstream 1.007 0 0 1.007 45.168 813.037 cm /Length 16 Q: A number increased by 5 is equivalent to twice the same number decreased by 7. /Resources<< /Meta156 Do 361 0 obj /FormType 1 /ProcSet[/PDF/Text] q 0 G 1 i /Type /XObject stream Q 0.786 Tc >> BT /Kids [ (2) Tj endstream stream /XObject << Q q q /Meta399 Do endstream >> /Font << q /Subtype /Form /BBox [0 0 30.642 16.44] /Meta333 Do q /Subtype /Form >> 41.186 5.203 TD Q q /Font << /Type /XObject /FormType 1 0 w /Type /XObject Q 1 g ET /Length 12 Q >> 1.007 0 0 1.007 130.989 330.484 cm /Contents [446 0 R] /Type /XObject 1 i q /Length 69 /Matrix [1 0 0 1 0 0] /Resources<< /F3 17 0 R 1 i q >> 0.838 Tc endobj >> 1 i >> /FormType 1 Q endstream /Matrix [1 0 0 1 0 0] >> q (-11) Tj Q stream /Resources<< Q 1.502 5.203 TD endstream q /Font << 127 0 obj 0 G 355 0 obj >> >> Q ET stream /Subtype /Form >> 0.737 w /Meta221 235 0 R /Font << /Type /XObject /Meta330 Do >> 1 i 0 20.154 m /Font << q 1.014 0 0 1.007 251.439 636.879 cm q 1.005 0 0 1.007 102.382 293.596 cm Q /BBox [0 0 88.214 16.44] /Meta291 Do [( subt)-17(racted fr)-14(om a )-16(number)] TJ /ProcSet[/PDF/Text] (3\)) Tj q /Meta93 Do >> Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . /Meta283 Do 151 0 obj q 0 G /Subtype /Form endstream S 1 g Q /Subtype /Form 0.564 G endobj /Meta110 124 0 R 1.007 0 0 1.007 411.035 277.035 cm /FormType 1 << >> 19.474 5.203 TD stream /Widths [ 250 0 0 0 0 0 0 0 333 333 0 0 250 0 q 1 g q /Resources<< /BBox [0 0 88.214 16.44] 1 i /ProcSet[/PDF/Text] /F3 12.131 Tf BT 0 g stream q /Resources<< /Meta109 123 0 R q /Matrix [1 0 0 1 0 0] /FormType 1 >> /F1 7 0 R /Meta4 Do ET Q >> q q /Subtype /Form Q /Meta420 436 0 R /Length 69 /Subtype /Form 1 i 1.007 0 0 1.006 130.989 690.329 cm /FormType 1 q /Type /XObject /FormType 1 0 g 0.458 0 0 RG Q /ProcSet[/PDF/Text] q stream q 1.005 0 0 1.007 79.798 813.037 cm q 388 0 obj (x ) Tj /Type /XObject /Type /XObject /Type /XObject endobj stream 1.007 0 0 1.007 130.989 776.149 cm endobj >> >> Q endobj stream 0 w /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] >> 1.014 0 0 1.007 251.439 583.429 cm endstream q BT Transcribed Image Text: A number increased by 5 is equivalent to twice the same number decreased by 7. /BBox [0 0 15.59 16.44] /F3 12.131 Tf 58 decreased by twice Gails age. 130 0 obj 1 i /ProcSet[/PDF/Text] Q 2.238 5.203 TD << Q ET /Subtype /Form /ProcSet[/PDF/Text] 306 0 obj 20 0 obj /Meta332 Do 1 i q /ProcSet[/PDF/Text] /Meta399 415 0 R 23.216 5.203 TD 0.737 w >> 0.737 w 0.297 Tc 0 g endobj /ProcSet[/PDF/Text] Q << (-23) Tj /Type /XObject /Type /XObject 1 i endstream /F3 12.131 Tf endobj q /Matrix [1 0 0 1 0 0] q stream Q endstream /Resources<< 0.786 Tc >> S Q /BBox [0 0 639.552 16.44] Q q endstream 1.502 5.203 TD Q q Q >> /Type /XObject stream 1.007 0 0 1.006 551.058 763.351 cm (C) Tj 1 g q /F3 12.131 Tf /Type /XObject /FormType 1 239 0 obj Q endobj q q endobj 55 0 obj q << /Meta418 Do /Matrix [1 0 0 1 0 0] /Subtype /Form 1.014 0 0 1.007 251.439 776.149 cm endobj /ProcSet[/PDF/Text] 1.007 0 0 1.007 551.058 330.484 cm /Subtype /Form >> 0.458 0 0 RG Q Q >> endobj Let x the unknown number. (+) Tj Q >> endstream /Meta9 20 0 R 104 0 obj /FormType 1 1 g q 0 g Q Q /Meta414 430 0 R /Font << /Resources<< BT 0 w /ProcSet[/PDF/Text] /FormType 1 340 0 obj 0 g /Matrix [1 0 0 1 0 0] stream Q /Subtype /Form Q q /Resources<< ET 1.007 0 0 1.007 411.035 383.934 cm q q q Q 158 0 obj /Font << 47.933 5.203 TD /F3 12.131 Tf stream 0.458 0 0 RG 0 w /Meta341 Do 1.005 0 0 1.007 102.382 347.046 cm /Matrix [1 0 0 1 0 0] /Type /XObject >> q >> BT 43.426 5.203 TD q /Matrix [1 0 0 1 0 0] /F3 12.131 Tf >> /Meta201 Do /Length 69 >> >> q endobj /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Type /XObject q /FormType 1 /Meta153 167 0 R /Type /XObject 14.966 20.154 l /BBox [0 0 88.214 16.44] << BT /Resources<< stream << 0.175 Tc /BBox [0 0 534.67 16.44] stream Q /Resources<< q /Meta338 Do 0.458 0 0 RG 1 i 0 g /Subtype /Form /ProcSet[/PDF/Text] (x) Tj /Length 69 Q Q >> q >> 1.007 0 0 1.007 411.035 636.879 cm /Resources<< Q /BBox [0 0 88.214 16.44] 32 0 obj /ProcSet[/PDF/Text] >> /Length 63 /Matrix [1 0 0 1 0 0] BT q 1.007 0 0 1.007 271.012 277.035 cm Q 0.564 G /MediaBox [0 0 767.868 993.712] Q >> endstream 1.005 0 0 1.007 79.798 713.666 cm 19.474 20.154 l >> /Meta167 181 0 R /Resources<< endobj /Matrix [1 0 0 1 0 0] /Type /XObject q Q 0 5.203 TD the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three . 1 i In other terms, 52-nxn = equals a number The problem is asking that you subtract twice a number from 52. /Meta118 Do /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] >> /Resources<< /F4 12.131 Tf 0 w 1 i >> /Meta254 Do /FormType 1 /Meta316 330 0 R stream q /Resources<< 0 g (B\)) Tj /FormType 1 0 w /Subtype /Form /F3 12.131 Tf q /BBox [0 0 88.214 35.886] endobj q q /Matrix [1 0 0 1 0 0] /FormType 1 Q /Length 69 /Meta401 417 0 R /Font << stream Hence, the number is 6. Q 1.007 0 0 1.007 45.168 813.037 cm /Meta60 Do /Matrix [1 0 0 1 0 0] stream /Resources<< endstream Q [(The )-16(s)15(um )-14(of )] TJ 369 0 obj 6.746 8.18 TD Q 1 i /Meta400 Do 0.458 0 0 RG 0.737 w >> q /Length 16 /Matrix [1 0 0 1 0 0] q stream ET 1 i >> /Meta304 Do 331 0 obj /Font << /ProcSet[/PDF/Text] 1.007 0 0 1.007 130.989 383.934 cm /ProcSet[/PDF] << Q /Meta25 Do /FormType 1 q /BBox [0 0 15.59 16.44] Q 94 0 obj ET /Resources<< 1.007 0 0 1.007 411.035 383.934 cm >> /ProcSet[/PDF/Text] << Q 76 0 obj /Matrix [1 0 0 1 0 0] 0 g 0 39.216 TD /Subtype /Form q Q 1 i q 0.458 0 0 RG q 0 5.203 TD 0 g /ProcSet[/PDF/Text] q q endstream << /Length 96 /I0 Do /Matrix [1 0 0 1 0 0] Q Q Q /Meta236 Do Q << stream /Length 69 /Matrix [1 0 0 1 0 0] /FormType 1 0.737 w /F3 17 0 R 0 g Q 1 i /Matrix [1 0 0 1 0 0] << endstream /Meta110 Do /Resources<< Q /Descent -216 /Subtype /Form /Meta124 138 0 R 0.737 w Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . /Subtype /Form >> /Font << You could call them, Decreased by another number means subtract. /Resources<< /F3 17 0 R /F3 17 0 R Q /Meta70 84 0 R /Type /XObject 1 i Q Q /FormType 1 Q /Resources<< /F3 12.131 Tf >> endobj /Subtype /Form 4.506 24.649 TD /F3 17 0 R >> << BT 0 G 0 5.203 TD /FormType 1 /Meta265 279 0 R /F1 7 0 R 0 G /Subtype /Form 20.21 5.203 TD >> 1.007 0 0 1.007 271.012 523.204 cm 1.007 0 0 1.007 67.753 799.486 cm 0.486 Tc -0.106 Tw 184 0 obj Q /BBox [0 0 88.214 16.44] BT 1 i Q /F1 7 0 R /Meta260 Do /Resources<< /Type /XObject /Font << q /F3 12.131 Tf 0 G endstream endstream endobj q /Resources<< /BBox [0 0 534.67 16.44] Q /BBox [0 0 88.214 35.886] endstream 1 i 1 g q 549.694 0 0 16.469 0 -0.0283 cm Q Q /Font << << << /ProcSet[/PDF/Text] /Meta32 45 0 R q >> q q endstream /Meta183 Do endobj /Matrix [1 0 0 1 0 0] /F3 17 0 R 0 g endobj >> 0 G 0.564 G >> /Meta37 Do 1.502 24.649 TD >> 0 g q BT q /Resources<< /Subtype /Form endstream << /Type /XObject /Meta86 Do 1.502 5.203 TD BT /Meta50 64 0 R q 1 g /F3 12.131 Tf endobj 1 i /Font << /Meta202 216 0 R 0.738 Tc 0 g endobj /Matrix [1 0 0 1 0 0] 1 i >> /Type /XObject Q /Meta230 Do 0.68 Tc /F3 12.131 Tf 0 G 1 i /FormType 1 stream /Length 118 [( the )-24(sum of a n)-14(umber an)-14(d )] TJ endstream >> /Meta208 222 0 R Q Q /Type /XObject 0 G /ProcSet[/PDF/Text] 0.738 Tc You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. endobj /F3 17 0 R endstream 0 w q q /F4 12.131 Tf Q /Length 58 stream 1.007 0 0 1.007 654.946 400.496 cm /Length 54 31 0 obj endstream endstream /Subtype /Form /Matrix [1 0 0 1 0 0] /Subtype /Form /Resources<< /Matrix [1 0 0 1 0 0] q /Type /XObject << /BBox [0 0 15.59 16.44] /Length 54 /F3 12.131 Tf BT 0 g /Length 13 /Length 294 /Length 99 /Resources<< /F4 36 0 R The symbols 17 + x = 68 form an algebraic equation. /Leading 349 /Matrix [1 0 0 1 0 0] Q gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. /Length 12 0 G /Meta252 Do 1.007 0 0 1.006 130.989 690.329 cm >> q 1 i Q 0.737 w 0 g 1.014 0 0 1.006 391.462 510.406 cm /BBox [0 0 88.214 35.886] 17.234 5.203 TD q /Subtype /Form 440 0 obj q (B) Tj q /Matrix [1 0 0 1 0 0] BT /Meta14 Do endstream endobj /Resources<< 1 i stream /F4 36 0 R Q 1 i Q >> /BBox [0 0 30.642 16.44] q q endobj q >> 72 0 obj 6 more than twice a number: 2x+6: two less than a number: x-2: the sum of 9 and a number: 9+x: two less than three times a number: 3x-2: a number subtracted from 12 . /BBox [0 0 15.59 16.44] >> endobj /Type /XObject 0 g 32.201 5.203 TD q /Font << /ProcSet[/PDF/Text] 0 w /ProcSet[/PDF/Text] stream 1 g Q /FormType 1 /Matrix [1 0 0 1 0 0] endstream 1 g /Matrix [1 0 0 1 0 0] 3.742 5.203 TD Q q << /Length 77 >> /Font << Q Q 5 0 obj >> endobj /Font << q 428 0 obj endobj >> >> [( and )16(a nu)26(mbe)18(r)] TJ endstream endobj q >> /BBox [0 0 88.214 16.44] /BBox [0 0 30.642 16.44] q 1.005 0 0 1.007 79.798 746.789 cm /Resources<< 1.007 0 0 1.007 271.012 849.172 cm << ET >> /Type /XObject /Meta40 54 0 R (D\)) Tj 0 w /Subtype /Form 1 i << 0 g 400 0 R /Length 16 >> >> /Font << 0 g Q Q endobj /Meta194 208 0 R Q /Meta348 Do q endstream >> /FormType 1 /F3 12.131 Tf 0.737 w /F3 17 0 R /F3 12.131 Tf 436 0 obj >> /XHeight 447 q stream /BBox [0 0 639.552 16.44] /FormType 1 /Meta315 329 0 R /Meta392 408 0 R Twice a number decreased by ten is at least 24. /BBox [0 0 88.214 16.44] Q BT q stream /BBox [0 0 534.67 16.44] >> >> Q BT 0 g /Resources<< Most questions answered within 4 hours. stream /FormType 1 >> >> /MaxWidth 2000 >> /BBox [0 0 23.896 16.44] << /Matrix [1 0 0 1 0 0] 380 0 obj (D\)) Tj /FormType 1 /F3 12.131 Tf q BT /Subtype /Form stream 26.957 5.203 TD /ProcSet[/PDF/Text] q ET /Resources<< 1 i (B) Tj stream >> /F1 7 0 R >> 0 G Q >> /Meta136 150 0 R stream << /Subtype /Form 1 g (-23) Tj >> /Subtype /Form 0 G /Meta29 42 0 R >> /BBox [0 0 88.214 16.44] /Meta362 Do